Do I need both v.27.0 & v.27.0.1 on my computer? Security risk?
On my Windows 7 64-bit desktop computer, on the page to remove programs, I have two versions of FireFox, 27.0 and 27.0.1. They both have (x86en-US) after their names. The 27.0.1 version is a week newer, of course. Is having the older version on there as well a security risk, like having old versions of Java, or is it harmless? Also, is there a 64 bit version of the browser I should be using? The current 32 bit version seems to work fine. Thanks for your help
Gekose oplossing
It's very unlikely that you have both Firefox 27.0 and 27.0.1 actually installed on your system.
Usually the installer for the latest version cleans up the section of the Windows registry that "Uninstall a Program" uses to generate that list. However, sometimes the clean-up fails.
Hopefully someone expert in how to clean it up manually will post a suggestion for that so you can get rid of the unnecessary extra entry.
Regarding 32-bit/64-bit versions of Firefox, no 64-bit version of Firefox is released. There is a 64-bit "nightly" version for developers, but because it has not even entered testing, I do not recommend using it.
Lees dié antwoord in konteks 👍 0All Replies (2)
I think one is Firefox, the other might just be the update. When I updated to version 28, the control panel said Firefox was installed days ago, but it's been on the computer for months. So no, it's not a problem.
Gewysig op deur user1068417
Gekose oplossing
It's very unlikely that you have both Firefox 27.0 and 27.0.1 actually installed on your system.
Usually the installer for the latest version cleans up the section of the Windows registry that "Uninstall a Program" uses to generate that list. However, sometimes the clean-up fails.
Hopefully someone expert in how to clean it up manually will post a suggestion for that so you can get rid of the unnecessary extra entry.
Regarding 32-bit/64-bit versions of Firefox, no 64-bit version of Firefox is released. There is a 64-bit "nightly" version for developers, but because it has not even entered testing, I do not recommend using it.