This site will have limited functionality while we undergo maintenance to improve your experience. If an article doesn't solve your issue and you want to ask a question, we have our support community waiting to help you at @FirefoxSupport on Twitter and/r/firefox on Reddit.

Search Support

Avoid support scams. We will never ask you to call or text a phone number or share personal information. Please report suspicious activity using the “Report Abuse” option.

Learn More

Under settings I need to find link for social and web accounts so I can reconnect to LinkedIn website

  • 1 reply
  • 1 has this problem
  • 7 views
  • Last reply by FredMcD

more options

I received an email notice from the LinkedIn web site that indicated that my free account will soon expire. I research on the internet how to re-active the account. The instructions to re-active the account were as follows: 1. Go to your Tools page; 2. Look under Settings and click the link for "Link social and web accounts"' 3. Click the reconnect link for your LinkedIn account. You'll be prompted to log in to LinkedIn if you are not currently logged in. My problem is when I finally found the "Settings" for Firefox there was nothing listed for the following: "Link social and web accounts". Thanks in advance for your help.

Regards

Irma

I received an email notice from the LinkedIn web site that indicated that my free account will soon expire. I research on the internet how to re-active the account. The instructions to re-active the account were as follows: 1. Go to your Tools page; 2. Look under Settings and click the link for "Link social and web accounts"' 3. Click the reconnect link for your LinkedIn account. You'll be prompted to log in to LinkedIn if you are not currently logged in. My problem is when I finally found the "Settings" for Firefox there was nothing listed for the following: "Link social and web accounts". Thanks in advance for your help. Regards Irma

All Replies (1)

more options

I think those instructions are for the website, not Firefox.